a2+b2=c2
) to two classes.I introduced the topic by drawing a right triangle on the board, labelling its angles A, B, and C in ascending order, then labelling the sides a, b, and c after their opposite angle. C is obviously the right angle, and c is the hypotenuse. I then stated the
a2+b2=c2
; illustrated that proposition by way of drawing a triangle abc with a square of the appropriate size on each side and proposed that we would, as a group, be proving that it is true (that it is a theorem).I introduced the students to two different dissection proofs of Pythagoras' Theorem:
- The first dissects two squares
(a+b)2
, one intoa2
,b2
and four triangles0.5ab
; and the other intoc2
and four triangles0.5ab
. We can describe the relationship between the areas of the two squares asa2+b2+2ab = c2+2ab
. The2ab
on each side cancel each other out (being trivially equal) and we are left witha2+b2=c2
. Q.E.D. - The second proof beings with a diagram of the square
c2
(drawn using four right triangles arranged within a square(a+b)2
). If we draw within thec2
four right triangles arranged to leave a gap in the centre (a square of(b-a)2
). These five pieces taken fromc2
can be rearranged to forma2+b2
. Q.E.D.
My colleague teacher (who usually teaches these classes) gave me a lot of feedback on my performance. I managed to miss many, many,
- introducing myself;
- beginning with a question (to find out what they already know and get them thinking about the topic);
- writing pertinent terms on the board (like "Pythagoras' Theorem" for example);
- structuring the lesson into 'direction' and 'doing' blocks effectively; and
- three pages of other bits and pieces.
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